Record be79cb7e2641480da244ad74c44a3095

Here is a short Python program.

```python
width = 4
rows = [5, 4, 5]
count = 2
widths = 6
row = [1, 4, 6]
widths = width + 8
row = row[1:]
rows = rows + [3]
batch = [3, 8]
scores = batch
scores += [13]
width += batch[-1]
extra = 4

def pack(num):
    return num * extra

extra += 2
width += pack(7)
width += len(rows)
width += count
width += len(row)
widths += count
widths += len(row)
```

After this program runs, what is the value of `width`? Work through it carefully, then give the final answer on its own last line as `ANSWER: <python literal>`.

To find the final value of `width`, let's trace the program step-by-step:

1.  `width = 4`
2.  `rows = [5, 4, 5]`
3.  `count = 2`
4.  `widths = 6`
5.  `row = [1, 4, 6]`
6.  `widths = width + 8` $\rightarrow$ `4 + 8 = 12`
7.  `row = row[1:]` $\rightarrow$ `row` becomes `[4, 6]`
8.  `rows = rows + [3]` $\rightarrow$ `rows` becomes `[5, 4, 5, 3]`
9.  `batch = [3, 8]`
10. `scores = batch` $\rightarrow$ `scores` is `[3, 8]`
11. `scores += [13]` $\rightarrow$ `scores` becomes `[3, 8, 13]`. Since `scores` and `batch` refer to the same list object, `batch` also becomes `[3, 8, 13]`.
12. `width += batch[-1]` $\rightarrow$ `batch[-1]` is `13`. `width = 4 + 13 = 17`.
13. `extra = 4`
14. Define function `pack(num)`: returns `num * extra`.
15. `extra += 2` $\rightarrow$ `extra` becomes `6`.
16. `width += pack(7)` $\rightarrow$ `pack(7)` returns `7 * 6 = 42`. `width = 17 + 42 = 59`.
17. `width += len(rows)` $\rightarrow$ `rows` is `[5, 4, 5, 3]`, so `len(rows)` is `4`. `width = 59 + 4 = 63`.
18. `width += count` $\rightarrow$ `count` is `2`. `width = 63 + 2 = 65`.
19. `width += len(row)` $\rightarrow$ `row` is `[4, 6]`, so `len(row)` is `2`. `width = 65 + 2 = 67`.
20. `widths += count` $\rightarrow$ `widths = 12 + 2 = 14`.
21. `widths += len(row)` $\rightarrow$ `widths = 14 + 2 = 16`.

The final value of `width` is 67.

ANSWER: 67

(no reasoning captured)