Record 66de88811f374997becda403b207b513

Here is a short Python program.

```python
scores = [7, 9, 5, 7]
limit = 7
peak = 8
limit = len(scores) % 3
for elem in scores:
    peak += elem
    limit = limit + 6
codes = scores
codes[0] = 13
shift = 5

def bump(q):
    return q + shift

shift = 11
scores.append(bump(6))

def boost(val):
    peak = val * 2 + 1
    return peak + 1

bonus = boost(7)
scores.append(peak + bonus)
for i in range(1, 5):
    scores.append(i)
offset = peak - 39
weight = offset % 6
scores.append(weight)

def tally_up(v, m=[]):
    m.append(v)
    return len(m) + v

extra = tally_up(6)
value = tally_up(6)
scores.append(value)
scores.append(limit * 2)
scores.append(peak)
```

After this program runs, what is the value of `scores`? Work through it carefully, then give the final answer on its own last line as `ANSWER: <python literal>`.

To find the final value of `scores`, let's trace the execution step-by-step:

1.  **Initialization:**
    *   `scores = [7, 9, 5, 7]`
    *   `limit = 7`
    *   `peak = 8`
    *   `limit = len(scores) % 3` $\rightarrow$ `4 % 3 = 1`

2.  **First Loop:**
    *   `for elem in scores:` (scores is `[7, 9, 5, 7]`)
    *   Iteration 1 (`elem=7`): `peak = 8 + 7 = 15`, `limit = 1 + 6 = 7`
    *   Iteration 2 (`elem=9`): `peak = 15 + 9 = 24`, `limit = 7 + 6 = 13`
    *   Iteration 3 (`elem=5`): `peak = 24 + 5 = 29`, `limit = 13 + 6 = 19`
    *   Iteration 4 (`elem=7`): `peak = 29 + 7 = 36`, `limit = 19 + 6 = 25`
    *   Current state: `scores = [7, 9, 5, 7]`, `peak = 36`, `limit = 25`

3.  **Reference Assignment:**
    *   `codes = scores` (Both variables now point to the same list object)
    *   `codes[0] = 13` $\rightarrow$ `scores` becomes `[13, 9, 5, 7]`
    *   `shift = 5`

4.  **Function `bump` and Append:**
    *   `def bump(q): return q + shift`
    *   `shift = 11`
    *   `scores.append(bump(6))` $\rightarrow$ `6 + 11 = 17`. `scores` is now `[13, 9, 5, 7, 17]`

5.  **Function `boost` and Append:**
    *   `def boost(val): peak = val * 2 + 1; return peak + 1`
    *   `bonus = boost(7)` $\rightarrow$ Local `peak` is $7 \times 2 + 1 = 15$. Returns $15 + 1 = 16$.
    *   `scores.append(peak + bonus)` $\rightarrow$ Global `peak` is 36. $36 + 16 = 52$.
    *   `scores` is now `[13, 9, 5, 7, 17, 52]`

6.  **Second Loop:**
    *   `for i in range(1, 5): scores.append(i)` $\rightarrow$ Appends 1, 2, 3, 4.
    *   `scores` is now `[13, 9, 5, 7, 17, 52, 1, 2, 3, 4]`

7.  **Offset and Weight:**
    *   `offset = peak - 39` $\rightarrow$ $36 - 39 = -3$
    *   `weight = offset % 6` $\rightarrow$ $-3 \pmod 6 = 3$
    *   `scores.append(weight)` $\rightarrow$ `scores` is now `[13, 9, 5, 7, 17, 52, 1, 2, 3, 4, 3]`

8.  **Function `tally_up` (Mutable Default Argument):**
    *   `def tally_up(v, m=[]): m.append(v); return len(m) + v`
    *   `extra = tally_up(6)` $\rightarrow$ `m` becomes `[6]`. Returns $1 + 6 = 7$.
    *   `value = tally_up(6)` $\rightarrow$ `m` becomes `[6, 6]`. Returns $2 + 6 = 8$.
    *   `scores.append(value)` $\rightarrow$ `scores` is now `[13, 9, 5, 7, 17, 52, 1, 2, 3, 4, 3, 8]`

9.  **Final Appends:**
    *   `scores.append(limit * 2)` $\rightarrow$ $25 \times 2 = 50$.
    *   `scores.append(peak)` $\rightarrow$ 36.
    *   `scores` is now `[13, 9, 5, 7, 17, 52, 1, 2, 3, 4, 3, 8, 50, 36]`

ANSWER: [13, 9, 5, 7, 17, 52, 1, 2, 3, 4, 3, 8, 50, 36]

(no reasoning captured)